f^2+22f+121=0

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Solution for f^2+22f+121=0 equation: 



f^2+22f+121=0

a = 1; b = 22; c = +121;
Δ = b2-4ac
Δ = 222-4·1·121
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$f=\frac{-b}{2a}=\frac{-22}{2}=-11$

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